What is the domain of f(x)=sqrt(x^2-6x) ?

The domain of f(x)=sqrt(x^2-6x) is x = 6

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domain of f(x)=sqrt(x^2-6x)

domain

f (x) = x^{2} - 6 x

x \leq 0 or x \geq 6

Interval Notation

(- \infty, 0] \cup [6, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 0 or x \geq 6

The function domain

x \leq 0 or x \geq 6

f (x) = (\frac{3}{2})^{x} - 2

f (x) = - 2 (3)^{x}

f (x) = 5 x

f (x) = - \frac{1}{3} x^{2} + 4 x + 11

x - 7 = 3

What is the domain of f(x)=sqrt(x^2-6x) ?
The domain of f(x)=sqrt(x^2-6x) is x<= 0\lor x>= 6