en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

range of f(x)=-x^2-4x-8

Solution

range

f (x) = - x^{2} - 4 x - 8

Solution

f (x) \leq - 4

+1

Interval Notation

(- \infty, - 4]

Solution steps

Vertex of

- x^{2} - 4 x - 8 :

Maximum

(- 2, - 4)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = - 1,

Vertex

(x_{v}, y_{v}) = (- 2, - 4)

f (x) \leq - 4

Popular Examples

extreme f(x)=-x^3+6x^2-14 extreme points

f (x) = - x^{3} + 6 x^{2} - 14

intercepts of f(x)=9-x^2 intercepts

f (x) = 9 - x^{2}

x - 4

inverse of f(x)=0.75^x inverse

f (x) = 0.7 5^{x}

asymptotes of f(x)=((x^4))/(x-2)asymptotes

f (x) = \frac{( x ^{4} )}{x - 2}

Frequently Asked Questions (FAQ)

What is the range of f(x)=-x^2-4x-8 ?
The range of f(x)=-x^2-4x-8 is f(x)<=-4