What is the domain of f(x)=sqrt(1-2x) ?

The domain of f(x)=sqrt(1-2x) is x<= 1/2

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domain of f(x)=sqrt(1-2x)

domain

f (x) = 1 - 2 x

x \leq \frac{1}{2}

Interval Notation

(- \infty, \frac{1}{2}]

Solution steps

Find non-negative values for radicals:

x \leq \frac{1}{2}

The function domain

x \leq \frac{1}{2}

- 16 (x + 7)^{2} - 3

f (x) = \frac{x - 3}{x ^{2} + 6 x + 9}

\frac{- x - 2}{11}

f (x) = \frac{2}{( \frac{x}{x + 2} )}

f (x) = \frac{2 x}{x ^{2} + x + 1}

What is the domain of f(x)=sqrt(1-2x) ?
The domain of f(x)=sqrt(1-2x) is x<= 1/2