What is the extreme f(x)=x^3-x^2-x+5 ?

The extreme f(x)=x^3-x^2-x+5 is Maximum(-1/3 , 140/27),Minimum(1,4)

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extreme f(x)=x^3-x^2-x+5

extreme points

f (x) = x^{3} - x^{2} - x + 5

Maximum (- \frac{1}{3}, \frac{140}{27}), Minimum (1, 4)

Solution steps

f^{'} (x) = 3 x^{2} - 2 x - 1

Find intervals:

Increasing

: - \infty < x < - \frac{1}{3},

Decreasing

: - \frac{1}{3} < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - \frac{1}{3}

into

x^{3} - x^{2} - x + 5 : \frac{140}{27}

Maximum (- \frac{1}{3}, \frac{140}{27})

Plug

x = 1

into

x^{3} - x^{2} - x + 5 : 4

Minimum (1, 4)

Maximum (- \frac{1}{3}, \frac{140}{27}), Minimum (1, 4)

f (x) = \frac{x}{x ^{3} - 1}

f (x) = 3 x^{3} + 7 y = 6

4 x + 10 y = 70

- 2 sin (x)

f (x) = 3 x - 2

What is the extreme f(x)=x^3-x^2-x+5 ?
The extreme f(x)=x^3-x^2-x+5 is Maximum(-1/3 , 140/27),Minimum(1,4)