What is the inverse of f(x)=-2(x-3)^2+5 ?

The inverse of f(x)=-2(x-3)^2+5 is sqrt(-(x-5)/2)+3,-sqrt(-(x-5)/2)+3

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inverse of f(x)=-2(x-3)^2+5

inverse

f (x) = - 2 (x - 3)^{2} + 5

- \frac{x - 5}{2} + 3, - - \frac{x - 5}{2} + 3

Solution steps

y = - 2 (x - 3)^{2} + 5

Replace

x

with

y

x = - 2 (y - 3)^{2} + 5

Solve for

y, x = - 2 (y - 3)^{2} + 5

- \frac{x - 5}{2} + 3, - - \frac{x - 5}{2} + 3

7 lo g_{7} (x)

f (x) = - ln (x - 2)

sin (θ) + cos (θ)

x^{2} + 1

f (x) = e^{a r c t a n (x)}

What is the inverse of f(x)=-2(x-3)^2+5 ?
The inverse of f(x)=-2(x-3)^2+5 is sqrt(-(x-5)/2)+3,-sqrt(-(x-5)/2)+3