What is the domain of sqrt(x^2-64) ?

The domain of sqrt(x^2-64) is x = 8

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domain of sqrt(x^2-64)

domain

x^{2} - 64

x \leq - 8 or x \geq 8

Interval Notation

(- \infty, - 8] \cup [8, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 8 or x \geq 8

The function domain

x \leq - 8 or x \geq 8

f (x) = \frac{x + 5}{2 x - 1}

f (x) = \frac{3 x - 8}{7 + 3 x}

f (x) = \frac{3 x}{x ( x ^{2} - 25 )}

\frac{x ^{3} + 5}{x}

(1, 2), (0, 5)

What is the domain of sqrt(x^2-64) ?
The domain of sqrt(x^2-64) is x<=-8\lor x>= 8