What is the inverse of f(x)=(4-3x)^{7/2} ?

The inverse of f(x)=(4-3x)^{7/2} is -(x^{2/7}-4)/3

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inverse of f(x)=(4-3x)^{7/2}

inverse

f (x) = (4 - 3 x)^{\frac{7}{2}}

- \frac{x ^{\frac{2}{7}} - 4}{3}

Solution steps

y = (4 - 3 x)^{\frac{7}{2}}

Replace

x

with

y

x = (4 - 3 y)^{\frac{7}{2}}

Solve for

y, x = (4 - 3 y)^{\frac{7}{2}}

- \frac{x ^{\frac{2}{7}} - 4}{3}

y = - x + 2

\frac{d v}{tan ( v )}

f (x) = ((3 + x) ∣ (x))

f (x) = x^{4} - 242 x^{2} + 14641

x^{6} (x - 2)^{5}

What is the inverse of f(x)=(4-3x)^{7/2} ?
The inverse of f(x)=(4-3x)^{7/2} is -(x^{2/7}-4)/3