What is the domain of g(x)=(sqrt(x))/(4x^2+3x-1) ?

The domain of g(x)=(sqrt(x))/(4x^2+3x-1) is 0 1/4

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domain of g(x)=(sqrt(x))/(4x^2+3x-1)

domain

g (x) = \frac{x}{4 x ^{2} + 3 x - 1}

0 \leq x < \frac{1}{4} or x > \frac{1}{4}

Interval Notation

Solution steps

Find non-negative values for radicals:

x \geq 0

Find undefined (singularity) points:

x = \frac{1}{4}, x = - 1

Combine real regions and undefined points for final function domain

0 \leq x < \frac{1}{4} or x > \frac{1}{4}

f, f > 1

- ∣ x - 3 ∣ + 2

y = \frac{- 3}{4} + 2

f (x) = \frac{- 5 x - 5}{3 x + 3}

f (x) = \frac{3 x - 5}{2 x + 3}

What is the domain of g(x)=(sqrt(x))/(4x^2+3x-1) ?
The domain of g(x)=(sqrt(x))/(4x^2+3x-1) is 0<= x< 1/4 \lor x> 1/4