What is the intercepts of f(x)=2x^2+7x-4 ?

The intercepts of f(x)=2x^2+7x-4 is X Intercepts: (1/2 ,0),(-4,0),Y Intercepts: (0,-4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

intercepts of f(x)=2x^2+7x-4

intercepts

f (x) = 2 x^{2} + 7 x - 4

X Intercepts : (\frac{1}{2}, 0), (- 4, 0), Y Intercepts : (0, - 4)

Solution steps

x -

axis interception points of

2 x^{2} + 7 x - 4 : (\frac{1}{2}, 0), (- 4, 0)

y -

axis interception point of

2 x^{2} + 7 x - 4 : (0, - 4)

X Intercepts : (\frac{1}{2}, 0), (- 4, 0), Y Intercepts : (0, - 4)

x + 4 - x

(3, 0), (3, - 6)

f (x) = - 3 x^{2} - 42 x - 22

f (x) = x - 3

4 x - 5

What is the intercepts of f(x)=2x^2+7x-4 ?
The intercepts of f(x)=2x^2+7x-4 is X Intercepts: (1/2 ,0),(-4,0),Y Intercepts: (0,-4)