What is the critical y= 1/(x^2)-1/x ?

The critical y= 1/(x^2)-1/x is x=2

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critical y= 1/(x^2)-1/x

critical points

y = \frac{1}{x ^{2}} - \frac{1}{x}

x = 2

Solution steps

\frac{1}{x ^{2}} - \frac{1}{x}

Find where

f^{'} (x)

is equal to zero or undefined

x = 2, x = 0

Identify critical points not in

f (x)

domain

Domain of

\frac{1}{x ^{2}} - \frac{1}{x} : x < 0 or x > 0

\frac{1}{x ^{2}} - \frac{1}{x}

is not defined at

x = 0

, therefore:

x = 2

\frac{e ^{x}}{7 + e ^{x}}

(0, 1), (1, 3)

f (x) = \frac{2}{x ^{2}}

x^{4} + x^{2}

\frac{x}{x ^{2} + 25}