What is the asymptotes of f(x)=((x+1)^2)/(x^2-3x-4) ?

The asymptotes of f(x)=((x+1)^2)/(x^2-3x-4) is Vertical: x=4,Horizontal: y=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of f(x)=((x+1)^2)/(x^2-3x-4)

asymptotes

f (x) = \frac{( x + 1 ) ^{2}}{x ^{2} - 3 x - 4}

Vertical : x = 4, Horizontal : y = 1

Solution steps

Vertical asymptotes of

\frac{( x + 1 ) ^{2}}{x ^{2} - 3 x - 4} : x = 4

Horizontal Asymptotes of

\frac{( x + 1 ) ^{2}}{x ^{2} - 3 x - 4} : y = 1

Slant Asymptotes of

\frac{( x + 1 ) ^{2}}{x ^{2} - 3 x - 4} :

None

Vertical : x = 4, Horizontal : y = 1

y = - 2 x + 6

f (x) = 4 x^{3} + 4 x^{2} - 3 x - 1

\frac{e ^{x} - 1}{e ^{x} + 1}

g (x) = 3 x

What is the asymptotes of f(x)=((x+1)^2)/(x^2-3x-4) ?
The asymptotes of f(x)=((x+1)^2)/(x^2-3x-4) is Vertical: x=4,Horizontal: y=1