What is the perpendicular y=-4x+3,(8,1) ?

The perpendicular y=-4x+3,(8,1) is y= 1/4 x-1

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perpendicular y=-4x+3,(8,1)

perpendicular

y = - 4 x + 3, (8, 1)

y = \frac{1}{4} x - 1

Solution steps

Find the line

y = mx + b

perpendicular to

y = - 4 x + 3

that passes through

(8, 1)

Find the slope of

y = - 4 x + 3 : m = - 4

Compute the slope of the perpendicular line:

m_{p} = \frac{1}{4}

Find the line with slope m=

\frac{1}{4}

and passing through

(8, 1) : y = \frac{1}{4} x - 1

y = \frac{1}{4} x - 1

f (x) = \frac{1}{x}

\frac{( ( x + 2 ) ( x - 3 ) )}{2 x ^{2}}

f (x) = \frac{1}{4 x - x ^{2}}

f (x) = \frac{x ^{2}}{( x ^{3} + 8 )}

f (x) = \frac{7 x - 3}{5 x - 9}

What is the perpendicular y=-4x+3,(8,1) ?
The perpendicular y=-4x+3,(8,1) is y= 1/4 x-1