What is the critical 4x^3+7x^2-10x-8 ?

The critical 4x^3+7x^2-10x-8 is x=-5/3 ,x= 1/2

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critical 4x^3+7x^2-10x-8

critical points

4 x^{3} + 7 x^{2} - 10 x - 8

x = - \frac{5}{3}, x = \frac{1}{2}

Solution steps

4 x^{3} + 7 x^{2} - 10 x - 8

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{5}{3}, x = \frac{1}{2}

Identify critical points not in

f (x)

domain

Domain of

4 x^{3} + 7 x^{2} - 10 x - 8 : - \infty < x < \infty

All critical points are in domain

x = - \frac{5}{3}, x = \frac{1}{2}

f (x) = \frac{- 9}{x ^{2} + 6}

f (x) = 18 - 5 x

(6.3) (8.1)

f (x) = x^{4} + 50 x^{2} + 625

f (x) = - 2 (x + 1)^{2} - 3, x \geq 1

What is the critical 4x^3+7x^2-10x-8 ?
The critical 4x^3+7x^2-10x-8 is x=-5/3 ,x= 1/2