What is the perpendicular y=-1/9 x-8/9 ,(1,-4) ?

The perpendicular y=-1/9 x-8/9 ,(1,-4) is y=9x-13

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perpendicular y=-1/9 x-8/9 ,(1,-4)

perpendicular

y = - \frac{1}{9} x - \frac{8}{9}, (1, - 4)

y = 9 x - 13

Solution steps

Find the line

y = mx + b

perpendicular to

y = - \frac{1}{9} x - \frac{8}{9}

that passes through

(1, - 4)

Find the slope of

y = - \frac{1}{9} x - \frac{8}{9} : m = - \frac{1}{9}

Compute the slope of the perpendicular line:

m_{p} = 9

Find the line with slope m=

9

and passing through

(1, - 4) : y = 9 x - 13

y = 9 x - 13

y = arccos (x)

sin (2.8 x + 0.9) + 0.3

f (x) = \frac{( x ^{2} )}{x + 1}

f (x) = ln (x)

a x + c = 0

What is the perpendicular y=-1/9 x-8/9 ,(1,-4) ?
The perpendicular y=-1/9 x-8/9 ,(1,-4) is y=9x-13