What is the critical f(x)=2x^2-6x^4 ?

The critical f(x)=2x^2-6x^4 is x=-1/(sqrt(6)),x=0,x= 1/(sqrt(6))

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critical f(x)=2x^2-6x^4

critical points

f (x) = 2 x^{2} - 6 x^{4}

x = - \frac{1}{6}, x = 0, x = \frac{1}{6}

Solution steps

2 x^{2} - 6 x^{4}

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{1}{6}, x = 0, x = \frac{1}{6}

Identify critical points not in

f (x)

domain

Domain of

2 x^{2} - 6 x^{4} : - \infty < x < \infty

All critical points are in domain

x = - \frac{1}{6}, x = 0, x = \frac{1}{6}

f (x) = \frac{1}{x ( x + 3 )}

(- 3, 2), (3, - 7)

f (x) = x^{2} - 14 x + 49

- 7 y + 2 x = 18

g (x) = e \frac{x}{( 3 x )}, x > 0

What is the critical f(x)=2x^2-6x^4 ?
The critical f(x)=2x^2-6x^4 is x=-1/(sqrt(6)),x=0,x= 1/(sqrt(6))