What is the domain of f(x)=-7/(2t^{3/2)} ?

The domain of f(x)=-7/(2t^{3/2)} is t>0

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domain of f(x)=-7/(2t^{3/2)}

domain

f (x) = - \frac{7}{2 t ^{\frac{3}{2}}}

t > 0

Interval Notation

(0, \infty)

Solution steps

Find non-negative values for radicals:

t \geq 0

Find undefined (singularity) points:

t = 0

Combine real regions and undefined points for final function domain

t > 0

f (x) = \frac{3 x}{x - 5}

x - 7 = 0

\frac{x}{x ^{2} + 9}

2 x - 3 y = 9

t + 3

What is the domain of f(x)=-7/(2t^{3/2)} ?
The domain of f(x)=-7/(2t^{3/2)} is t>0