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Popular >

inflection y=-x^3+12x-16

Solution

inflection points

y = - x^{3} + 12 x - 16

Solution

(0, - 16)

Solution steps

f^{''} (x) = - 6 x

Find intervals:

Concave Upward

: - \infty < x < 0,

Concave Downward

: 0 < x < \infty

Plug

x = 0

into

- x^{3} + 12 x - 16 : - 16

(0, - 16)

Popular Examples

distance (6,-2),(-5,5)distance

(6, - 2), (- 5, 5)

parallel 2x-4y+5=0,(-2,4)parallel

2 x - 4 y + 5 = 0, (- 2, 4)

domain of sqrt(1+2/x)domain

1 + \frac{2}{x}

inverse of f(x)=-2/3 x-8 inverse

f (x) = - \frac{2}{3} x - 8

inverse of f(x)=(-3-2x)/3 inverse

f (x) = \frac{- 3 - 2 x}{3}

Frequently Asked Questions (FAQ)

What is the inflection y=-x^3+12x-16 ?
The inflection y=-x^3+12x-16 is (0,-16)