What is the domain of f(x)= 1/(x^2-2x-3) ?

The domain of f(x)= 1/(x^2-2x-3) is x 3

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domain of f(x)= 1/(x^2-2x-3)

domain

f (x) = \frac{1}{x ^{2} - 2 x - 3}

x < - 1 or - 1 < x < 3 or x > 3

Interval Notation

(- \infty, - 1) \cup (- 1, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 1

The function domain

x < - 1 or - 1 < x < 3 or x > 3

f (x) = (2 x - 3)^{2} - 1

f (x) = \frac{7}{x ^{2} + 1}

f (x) = \frac{4}{x + 4}

f (x) = \frac{2 x - 6}{- x + 4}

f (x) = x^{2} + y = 36

What is the domain of f(x)= 1/(x^2-2x-3) ?
The domain of f(x)= 1/(x^2-2x-3) is x<-1\lor-1<x<3\lor x>3