What is the inverse of f(x)=x^2+3x+1 ?

The inverse of f(x)=x^2+3x+1 is (-3+sqrt(4x+5))/2 ,(-3-sqrt(4x+5))/2

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inverse of f(x)=x^2+3x+1

inverse

f (x) = x^{2} + 3 x + 1

\frac{- 3 + 4 x + 5}{2}, \frac{- 3 - 4 x + 5}{2}

Solution steps

y = x^{2} + 3 x + 1

Replace

x

with

y

x = y^{2} + 3 y + 1

Solve for

y, x = y^{2} + 3 y + 1

\frac{- 3 + 4 x + 5}{2}, \frac{- 3 - 4 x + 5}{2}

f (x) = \frac{1}{x ^{2} - 9}

f (g) = g

(- 4, - 5), (- 2, - 6)

(3, 4), (- 3, 2)

f (x) = - 7 - \frac{7}{4} x

What is the inverse of f(x)=x^2+3x+1 ?
The inverse of f(x)=x^2+3x+1 is (-3+sqrt(4x+5))/2 ,(-3-sqrt(4x+5))/2