What is the range of r(x)= 1/(x-2) ?

The range of r(x)= 1/(x-2) is f(x) 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

range of r(x)= 1/(x-2)

range

r (x) = \frac{1}{x - 2}

f (x) < 0 or f (x) > 0

Interval Notation

(- \infty, 0) \cup (0, \infty)

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

\frac{1}{x - 2}

Inverse of

\frac{1}{x - 2} : \frac{1}{x} + 2

\frac{1}{x} + 2

Find the domain of each inverse function

Domain of

\frac{1}{x} + 2 : x < 0 or x > 0

Combine the intervals

f (x) < 0 or f (x) > 0

x^{\frac{2}{3}} (1 - x)

- 4 - 2 cos (5 x)

f (x) = x^{\frac{1}{3}} - 9

f (x) = \frac{4 x ^{2} - 5}{2 x ^{3} + x}

4 x + 3 y = 9

What is the range of r(x)= 1/(x-2) ?
The range of r(x)= 1/(x-2) is f(x)<0\lor f(x)>0