What is the inverse of f(x)=x^2-8x ?

The inverse of f(x)=x^2-8x is 4+sqrt(x+16),4-sqrt(x+16)

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inverse of f(x)=x^2-8x

inverse

f (x) = x^{2} - 8 x

4 + x + 16, 4 - x + 16

Solution steps

y = x^{2} - 8 x

Replace

x

with

y

x = y^{2} - 8 y

Solve for

y, x = y^{2} - 8 y

4 + x + 16, 4 - x + 16

\frac{4 x - 8}{( x ( x - 2 ) )}

f (x) = e^{x} - x

f (x) = - x + 6

y^{2} = x + 144

5 cot (x)

What is the inverse of f(x)=x^2-8x ?
The inverse of f(x)=x^2-8x is 4+sqrt(x+16),4-sqrt(x+16)