What is the domain of f(x)=(18x^2+48x)/((8x-3)^2) ?

The domain of f(x)=(18x^2+48x)/((8x-3)^2) is x 3/8

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domain of f(x)=(18x^2+48x)/((8x-3)^2)

domain

f (x) = \frac{18 x ^{2} + 48 x}{( 8 x - 3 ) ^{2}}

x < \frac{3}{8} or x > \frac{3}{8}

Interval Notation

(- \infty, \frac{3}{8}) \cup (\frac{3}{8}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{3}{8}

The function domain

x < \frac{3}{8} or x > \frac{3}{8}

(- 2, 7), (7, 9)

\frac{3 x}{7 x - 6}

f (x) = ∣ x ∣

f (x) = \frac{x + 3}{x ( x - 6 )}

y = x^{2} + 10 x + 25

What is the domain of f(x)=(18x^2+48x)/((8x-3)^2) ?
The domain of f(x)=(18x^2+48x)/((8x-3)^2) is x< 3/8 \lor x> 3/8