What is the domain of f(x)=(sqrt(x-7))^2 ?

The domain of f(x)=(sqrt(x-7))^2 is x>= 7

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domain of f(x)=(sqrt(x-7))^2

domain

f (x) = (x - 7)^{2}

x \geq 7

Interval Notation

[7, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 7

The function domain

x \geq 7

y = - x^{2} + 7 x + 1

2 cos (x) - sin (2 x)

f (x) = \frac{4}{x + 6}

f (x) = \frac{6 x - 6}{x + 2}

f (x) = x + 8

What is the domain of f(x)=(sqrt(x-7))^2 ?
The domain of f(x)=(sqrt(x-7))^2 is x>= 7