What is the range of f(x)=g(x)=(x+3)2-1 ?

The range of f(x)=g(x)=(x+3)2-1 is -infinity <f(x)<infinity

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range of f(x)=g(x)=(x+3)2-1

range

f (x) = g (x) = (x + 3) 2 - 1

- \infty < f (x) < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The range of polynomials with odd degree is all the real numbers

- \infty < f (x) < \infty

x + 4 y = 8

f (4) = \frac{2}{5} x + 11

(- 4, 2), (3, - 3)

f (x) = \frac{8 x}{x + 7}

f (x) = 2

What is the range of f(x)=g(x)=(x+3)2-1 ?
The range of f(x)=g(x)=(x+3)2-1 is -infinity <f(x)<infinity