What is the critical x/(x^2-6x+8) ?

The critical x/(x^2-6x+8) is x=-2sqrt(2),x=2sqrt(2)

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critical x/(x^2-6x+8)

critical points

\frac{x}{x ^{2} - 6 x + 8}

x = - 22, x = 22

Solution steps

\frac{x}{x ^{2} - 6 x + 8}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 22, x = 22, x = 2, x = 4

Identify critical points not in

f (x)

domain

Domain of

\frac{x}{x ^{2} - 6 x + 8} : x < 2 or 2 < x < 4 or x > 4

\frac{x}{x ^{2} - 6 x + 8}

is not defined at

x = 2, x = 4

, therefore:

x = - 22, x = 22

f (x) = 7 x + 7 - 10

2 x + 5 y - 1 = 0

f (x) = \frac{400000 + 100 x}{x}

f (x) = x^{4} + 4 x^{3} - 48 x^{2} + 6

y = 2 x^{2} + 4 x + 5

What is the critical x/(x^2-6x+8) ?
The critical x/(x^2-6x+8) is x=-2sqrt(2),x=2sqrt(2)