What is the parallel x+3y=5,(-1,6) ?

The parallel x+3y=5,(-1,6) is y=-1/3 x+17/3

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parallel x+3y=5,(-1,6)

parallel

x + 3 y = 5, (- 1, 6)

y = - \frac{1}{3} x + \frac{17}{3}

Solution steps

Find the line

y = mx + b

parallel to

x + 3 y = 5

that passes through

(- 1, 6)

Find the slope of

x + 3 y = 5 : m = - \frac{1}{3}

Compute the

y

intercept:

b = \frac{17}{3}

Construct the line equation

y = mx + b

where

m = - \frac{1}{3}

and

b = \frac{17}{3}

y = - \frac{1}{3} x + \frac{17}{3}

2 tan (x - \frac{π}{4})

f (x) = x^{2} + 2 x + 5

f (x) = \frac{2 x ^{2} + x - 1}{x ^{2} + x - 2}

y - 1 = - 2 x

f (x) = x^{2} e^{- 3 x}

What is the parallel x+3y=5,(-1,6) ?
The parallel x+3y=5,(-1,6) is y=-1/3 x+17/3