What is the domain of f(x)=sqrt(x^2-4x-5) ?

The domain of f(x)=sqrt(x^2-4x-5) is x = 5

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domain of f(x)=sqrt(x^2-4x-5)

domain

f (x) = x^{2} - 4 x - 5

x \leq - 1 or x \geq 5

Interval Notation

(- \infty, - 1] \cup [5, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 1 or x \geq 5

The function domain

x \leq - 1 or x \geq 5

f (θ) = cos (θ)

\frac{5 x - 3}{x - 1}

(4 x)^{2}

f (x) = - x^{3} + 3 x^{2} - 5

f (x) = - x^{2} + 9

What is the domain of f(x)=sqrt(x^2-4x-5) ?
The domain of f(x)=sqrt(x^2-4x-5) is x<=-1\lor x>= 5