What is the monotone f(x)=(-5x+1)^2 ?

The monotone f(x)=(-5x+1)^2 is Decreasing:-infinity <x< 1/5 ,Increasing: 1/5 <x<infinity

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monotone f(x)=(-5x+1)^2

monotone intervals

f (x) = (- 5 x + 1)^{2}

Decreasing : - \infty < x < \frac{1}{5}, Increasing : \frac{1}{5} < x < \infty

Solution steps

f^{'} (x) = - 10 (- 5 x + 1)

Find intervals:

Decreasing

: - \infty < x < \frac{1}{5},

Increasing

: \frac{1}{5} < x < \infty

Decreasing : - \infty < x < \frac{1}{5}, Increasing : \frac{1}{5} < x < \infty

f (x) = \frac{2 x}{x ^{2} - 9}

4 cos (\frac{1}{3} x + \frac{π}{4}) + 1

- 4 + ln (x)

3 x - 2 y = 4

f (x) = sin (x^{3})

What is the monotone f(x)=(-5x+1)^2 ?
The monotone f(x)=(-5x+1)^2 is Decreasing:-infinity <x< 1/5 ,Increasing: 1/5 <x<infinity