What is the inverse of f(x)=x^2+4x+7 ?

The inverse of f(x)=x^2+4x+7 is -2+sqrt(x-3),-sqrt(x-3)-2

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inverse of f(x)=x^2+4x+7

inverse

f (x) = x^{2} + 4 x + 7

- 2 + x - 3, - x - 3 - 2

Solution steps

y = x^{2} + 4 x + 7

Replace

x

with

y

x = y^{2} + 4 y + 7

Solve for

y, x = y^{2} + 4 y + 7

- 2 + x - 3, - x - 3 - 2

f (x) = \frac{1}{2} cot (4 x)

\frac{x ^{2} - 1}{x + 2}

x

y = - 5 x + 2, (- 1, 4)

f (x) = \frac{2 x ^{2} + x - 1}{x ^{2} - 1}

What is the inverse of f(x)=x^2+4x+7 ?
The inverse of f(x)=x^2+4x+7 is -2+sqrt(x-3),-sqrt(x-3)-2