What is the domain of f(x)=1+(6+x)^{1/2} ?

The domain of f(x)=1+(6+x)^{1/2} is x>=-6

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domain of f(x)=1+(6+x)^{1/2}

domain

f (x) = 1 + (6 + x)^{\frac{1}{2}}

x \geq - 6

Interval Notation

[- 6, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 6

The function domain

x \geq - 6

\frac{sin ( x )}{1 + cos ( x )}

\frac{4}{3} π x^{3}

f (x) = 5 x^{2} + 2

0.9 cos (0.5) (x + \frac{π}{10})

x^{4} - x^{2} + 2 x

What is the domain of f(x)=1+(6+x)^{1/2} ?
The domain of f(x)=1+(6+x)^{1/2} is x>=-6