What is the range of f(x)= 1/(sqrt(4-x^2)) ?

The range of f(x)= 1/(sqrt(4-x^2)) is f(x)>= 1/2

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range of f(x)= 1/(sqrt(4-x^2))

range

f (x) = \frac{1}{4 - x ^{2}}

f (x) \geq \frac{1}{2}

Interval Notation

[\frac{1}{2}, \infty)

Solution steps

Find the minimum and maximum value in each defined interval and unite the results

Domain of

\frac{1}{4 - x ^{2}} : - 2 < x < 2

Extreme Points of

\frac{1}{4 - x ^{2}} :

Minimum

(0, \frac{1}{2})

Find the range for the interval

- 2 < x < 2 : \frac{1}{2} \leq f (x) < \infty

Combine the ranges of all domain intervals to obtain the function range

f (x) \geq \frac{1}{2}

3 x^{\frac{2}{3}} - 2 x

f (x) = - 1 + x^{3}

f (x) = x + 5

x^{2} (x - 5) (x^{2} + 3)

(- 2, - 6), (2, - 11)

What is the range of f(x)= 1/(sqrt(4-x^2)) ?
The range of f(x)= 1/(sqrt(4-x^2)) is f(x)>= 1/2