What is the extreme f(x)=2+3/(1+(x+1)^2) ?

The extreme f(x)=2+3/(1+(x+1)^2) is Maximum(-1,5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=2+3/(1+(x+1)^2)

extreme points

f (x) = 2 + \frac{3}{1 + ( x + 1 ) ^{2}}

Maximum (- 1, 5)

Solution steps

f^{'} (x) = - \frac{6 ( x + 1 )}{( x ^{2} + 2 x + 2 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < \infty

Plug

x = - 1

into

2 + \frac{3}{1 + ( x + 1 ) ^{2}} : 5

Maximum (- 1, 5)

y = - 3 x

- 3 x^{2} + 12 x

f (x) = \frac{x - 3}{x + 1}

\frac{1}{a ^{\frac{1}{n}}}

tan^{2} (x)

What is the extreme f(x)=2+3/(1+(x+1)^2) ?
The extreme f(x)=2+3/(1+(x+1)^2) is Maximum(-1,5)