What is the asymptotes of f(x)=(x^3+1)/(x^2+2) ?

The asymptotes of f(x)=(x^3+1)/(x^2+2) is Slant: y=x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

asymptotes of f(x)=(x^3+1)/(x^2+2)

asymptotes

f (x) = \frac{x ^{3} + 1}{x ^{2} + 2}

Slant : y = x

Solution steps

Vertical asymptotes of

\frac{x ^{3} + 1}{x ^{2} + 2} :

None

Horizontal Asymptotes of

\frac{x ^{3} + 1}{x ^{2} + 2} :

None

Slant Asymptotes of

\frac{x ^{3} + 1}{x ^{2} + 2} : y = x

Slant : y = x

(3, 2), (- 10, 4)

f (x) = \frac{x + 2}{x - 1}

- x + 2 y = 6

f (x) = \frac{- 3 x ^{2} - 12 x}{5 x ^{2}}

f (x) = 4 x^{3} - 80 x^{2} + 400 x

What is the asymptotes of f(x)=(x^3+1)/(x^2+2) ?
The asymptotes of f(x)=(x^3+1)/(x^2+2) is Slant: y=x