What is the inverse of f(x)=\sqrt[3]{4-y}+2 ?

The inverse of f(x)=\sqrt[3]{4-y}+2 is -y^3+6y^2-12y+12

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=\sqrt[3]{4-y}+2

inverse

- y^{3} + 6 y^{2} - 12 y + 12

Solution steps

Replace

y

with

x

Solve for

- y^{3} + 6 y^{2} - 12 y + 12

\frac{1}{( x - 2 ) ^{2}}

\frac{x ^{2} + x + 1}{x}

(0, - 1), (- 5, - 2)

f (x) = 3 sin (4 x)

\frac{x ^{2} + 3 x}{x ^{2} - x}

What is the inverse of f(x)=\sqrt[3]{4-y}+2 ?
The inverse of f(x)=\sqrt[3]{4-y}+2 is -y^3+6y^2-12y+12