What is the domain of 2/(x^2+4x+3) ?

The domain of 2/(x^2+4x+3) is x -1

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domain of 2/(x^2+4x+3)

domain

\frac{2}{x ^{2} + 4 x + 3}

x < - 3 or - 3 < x < - 1 or x > - 1

Interval Notation

(- \infty, - 3) \cup (- 3, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1, x = - 3

The function domain

x < - 3 or - 3 < x < - 1 or x > - 1

\frac{x + 1}{x + 6}

f (x) = sin (2 x)

f (x) = 5 x + 9 + 1

f (x) = \frac{1}{9} (2 x (x + 1) - x - 10) + 1

f (x) = 5 x^{5} - 9

What is the domain of 2/(x^2+4x+3) ?
The domain of 2/(x^2+4x+3) is x<-3\lor-3<x<-1\lor x>-1