What is the inverse of f(x)=-3^{x-1}+6 ?

The inverse of f(x)=-3^{x-1}+6 is (ln(6-x))/(ln(3))+1

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inverse of f(x)=-3^{x-1}+6

inverse

f (x) = - 3^{x - 1} + 6

\frac{ln ( 6 - x )}{ln ( 3 )} + 1

Solution steps

y = - 3^{x - 1} + 6

Replace

x

with

y

x = - 3^{y - 1} + 6

Solve for

y, x = - 3^{y - 1} + 6

\frac{ln ( 6 - x )}{ln ( 3 )} + 1

f (x) = x^{6} (x - 4)^{5}

x - 2 y = - 4

f (x) = - \frac{1}{2} x + 1

f (x) = 1 + 2 x

\frac{4 x}{- 1 + 4 x}

What is the inverse of f(x)=-3^{x-1}+6 ?
The inverse of f(x)=-3^{x-1}+6 is (ln(6-x))/(ln(3))+1