What is the domain of f(x)= 1/(x^2-5) ?

The domain of f(x)= 1/(x^2-5) is x sqrt(5)

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domain of f(x)= 1/(x^2-5)

domain

f (x) = \frac{1}{x ^{2} - 5}

x < - 5 or - 5 < x < 5 or x > 5

Interval Notation

(- \infty, - 5) \cup (- 5, 5) \cup (5, \infty)

Solution steps

Find undefined (singularity) points:

x = 5, x = - 5

The function domain

x < - 5 or - 5 < x < 5 or x > 5

f (x) = 5 - 2 x

y = \frac{5}{4} x - 7

y = \frac{3 x}{7 x + 14}

sin (2 x)

\frac{x - 3}{x - 2}

What is the domain of f(x)= 1/(x^2-5) ?
The domain of f(x)= 1/(x^2-5) is x<-sqrt(5)\lor-sqrt(5)<x<sqrt(5)\lor x>sqrt(5)