What is the inverse of y= 8/(x^2-6x+8) ?

The inverse of y= 8/(x^2-6x+8) is (3x+sqrt(x(x+8)))/x ,(3x-sqrt(x(x+8)))/x

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inverse of y= 8/(x^2-6x+8)

inverse

y = \frac{8}{x ^{2} - 6 x + 8}

\frac{3 x + x ( x + 8 )}{x}, \frac{3 x - x ( x + 8 )}{x}

Solution steps

y = \frac{8}{x ^{2} - 6 x + 8}

Replace

x

with

y

x = \frac{8}{y ^{2} - 6 y + 8}

Solve for

y, x = \frac{8}{y ^{2} - 6 y + 8}

\frac{3 x + x ( x + 8 )}{x}, \frac{3 x - x ( x + 8 )}{x}

f (x) = \frac{2}{2 x - 5}

(- 4, 3), (- 2, 1)

f (x) = \frac{3 x - 16}{x - 5}

f (x) = \frac{x ^{2} - 3}{2 x ^{2} - 18}

What is the inverse of y= 8/(x^2-6x+8) ?
The inverse of y= 8/(x^2-6x+8) is (3x+sqrt(x(x+8)))/x ,(3x-sqrt(x(x+8)))/x