What is the inverse of f(x)=((3x+1))/(x-2) ?

The inverse of f(x)=((3x+1))/(x-2) is (1+2x)/(x-3)

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inverse of f(x)=((3x+1))/(x-2)

inverse

f (x) = \frac{( 3 x + 1 )}{x - 2}

\frac{1 + 2 x}{x - 3}

Solution steps

y = \frac{3 x + 1}{x - 2}

Replace

x

with

y

x = \frac{3 y + 1}{y - 2}

Solve for

y, x = \frac{3 y + 1}{y - 2}

\frac{1 + 2 x}{x - 3}

f (x) = \frac{4 x ^{2} - 4 x}{x ^{2} + x - 12}

f (x) = (\frac{3 ^{x - 3}}{2})^{\frac{1}{3}}

lo g_{2} (x - 1)

f (x) = 3 x + 15

sin (2 x - 2 π)

What is the inverse of f(x)=((3x+1))/(x-2) ?
The inverse of f(x)=((3x+1))/(x-2) is (1+2x)/(x-3)