What is the asymptotes of f(x)=(x^2-3x)/(x^2-2x-8) ?

The asymptotes of f(x)=(x^2-3x)/(x^2-2x-8) is Vertical: x=-2,x=4,Horizontal: y=1

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asymptotes of f(x)=(x^2-3x)/(x^2-2x-8)

asymptotes

f (x) = \frac{x ^{2} - 3 x}{x ^{2} - 2 x - 8}

Vertical : x = - 2, x = 4, Horizontal : y = 1

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 3 x}{x ^{2} - 2 x - 8} : x = - 2, x = 4

Horizontal Asymptotes of

\frac{x ^{2} - 3 x}{x ^{2} - 2 x - 8} : y = 1

Slant Asymptotes of

\frac{x ^{2} - 3 x}{x ^{2} - 2 x - 8} :

None

Vertical : x = - 2, x = 4, Horizontal : y = 1

x^{2} ln (x)

e^{x} + 2

lo g_{10} (x)

2 (x + 1)^{2} - 3

(2, - 4), (- 4, 0)

What is the asymptotes of f(x)=(x^2-3x)/(x^2-2x-8) ?
The asymptotes of f(x)=(x^2-3x)/(x^2-2x-8) is Vertical: x=-2,x=4,Horizontal: y=1