What is the domain of f(x)=sqrt(x^2-4x-12) ?

The domain of f(x)=sqrt(x^2-4x-12) is x = 6

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domain of f(x)=sqrt(x^2-4x-12)

domain

f (x) = x^{2} - 4 x - 12

x \leq - 2 or x \geq 6

Interval Notation

(- \infty, - 2] \cup [6, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 2 or x \geq 6

The function domain

x \leq - 2 or x \geq 6

f (x) = \frac{2 x + 3}{5 - x}

f (x) = \frac{1}{2} x^{2} + 9 x + 8

(- 1) (- 3)

\frac{x ^{2} + 2 x - 3}{x ^{2} - 1}

f (x) = x^{2} - 9

What is the domain of f(x)=sqrt(x^2-4x-12) ?
The domain of f(x)=sqrt(x^2-4x-12) is x<=-2\lor x>= 6