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Popular >

distance (5,-1/7),(1,4)

Solution

distance

(5, - \frac{1}{7}), (1, 4)

Solution

\frac{5 65}{7}

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(5, - \frac{1}{7})

and

(1, 4)

is

= (1 - 5)^{2} + (4 - (- \frac{1}{7}))^{2}

Simplify

= \frac{5 65}{7}

Popular Examples

extreme y=390x-0.25x^3 extreme points

y = 390 x - 0.25 x^{3}

domain of f(x)=(sqrt(1-5x))/(3x-4)domain

f (x) = \frac{1 - 5 x}{3 x - 4}

domain of f(x)= 1/x+4 domain

f (x) = \frac{1}{x} + 4

line m=1,(-1,-11)line

m = 1, (- 1, - 11)

domain of f(x)=3(1-t)^2-2(1-t)+5 domain

f (x) = 3 (1 - t)^{2} - 2 (1 - t) + 5

Frequently Asked Questions (FAQ)

What is the distance (5,-1/7),(1,4) ?
The distance (5,-1/7),(1,4) is (5sqrt(65))/7