What is the asymptotes of f(x)=(2x^2-3)/(x+1) ?

The asymptotes of f(x)=(2x^2-3)/(x+1) is Vertical: x=-1,Slant: y=2x-2

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asymptotes of f(x)=(2x^2-3)/(x+1)

asymptotes

f (x) = \frac{2 x ^{2} - 3}{x + 1}

Vertical : x = - 1, Slant : y = 2 x - 2

Solution steps

Vertical asymptotes of

\frac{2 x ^{2} - 3}{x + 1} : x = - 1

Horizontal Asymptotes of

\frac{2 x ^{2} - 3}{x + 1} :

None

Slant Asymptotes of

\frac{2 x ^{2} - 3}{x + 1} : y = 2 x - 2

Vertical : x = - 1, Slant : y = 2 x - 2

3 (\frac{3}{5})^{x + 2} - 4

f (x) = x + 2 - x

4 x

- 2 x^{2} + 6 x + 10

f (x) = 5 - e^{x}

What is the asymptotes of f(x)=(2x^2-3)/(x+1) ?
The asymptotes of f(x)=(2x^2-3)/(x+1) is Vertical: x=-1,Slant: y=2x-2