What is the inverse of f(x)=((2x-1))/(x+1) ?

The inverse of f(x)=((2x-1))/(x+1) is (-1-x)/(x-2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=((2x-1))/(x+1)

inverse

f (x) = \frac{( 2 x - 1 )}{x + 1}

\frac{- 1 - x}{x - 2}

Solution steps

y = \frac{2 x - 1}{x + 1}

Replace

x

with

y

x = \frac{2 y - 1}{y + 1}

Solve for

y, x = \frac{2 y - 1}{y + 1}

\frac{- 1 - x}{x - 2}

f (x) = x^{2} - 3 x + 1

\frac{3 x - 6}{x - 2}

f (x) = \frac{3}{x ^{2}}

f (x) = ln (\frac{x}{x - 1})

f (x) = 3 + (6 + x)^{\frac{1}{2}}

What is the inverse of f(x)=((2x-1))/(x+1) ?
The inverse of f(x)=((2x-1))/(x+1) is (-1-x)/(x-2)