What is the extreme f(x)=x^3+3x^2-9x+4 ?

The extreme f(x)=x^3+3x^2-9x+4 is Maximum(-3,31),Minimum(1,-1)

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extreme f(x)=x^3+3x^2-9x+4

extreme points

f (x) = x^{3} + 3 x^{2} - 9 x + 4

Maximum (- 3, 31), Minimum (1, - 1)

Solution steps

f^{'} (x) = 3 x^{2} + 6 x - 9

Find intervals:

Increasing

: - \infty < x < - 3,

Decreasing

: - 3 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - 3

into

x^{3} + 3 x^{2} - 9 x + 4 : 31

Maximum (- 3, 31)

Plug

x = 1

into

x^{3} + 3 x^{2} - 9 x + 4 : - 1

Minimum (1, - 1)

Maximum (- 3, 31), Minimum (1, - 1)

y = 2 x + 5

x^{2} - 2 x

x^{14}

5 - x^{2}

f (x) = lo g_{5} (x)

What is the extreme f(x)=x^3+3x^2-9x+4 ?
The extreme f(x)=x^3+3x^2-9x+4 is Maximum(-3,31),Minimum(1,-1)