What is the domain of \sqrt[4]{x^5} ?

The domain of \sqrt[4]{x^5} is x>= 0

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domain of \sqrt[4]{x^5}

domain

x \geq 0

Interval Notation

[0, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

The function domain

x \geq 0

f (x) = \frac{4}{9 + x}

f (x) = \frac{1}{\frac{x}{\frac{1}{x} + 1}}

f (x) = 5 x - 7 x + 8

f (x) = \frac{9 x ^{3}}{x - 6}

\frac{x}{x ^{2} + 1}