What is the domain of f(x)= 1/(\frac{x){1/x+1}} ?

The domain of f(x)= 1/(\frac{x){1/x+1}} is x 0

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domain of f(x)= 1/(\frac{x){1/x+1}}

domain

f (x) = \frac{1}{\frac{x}{\frac{1}{x} + 1}}

x < - 1 or - 1 < x < 0 or x > 0

Interval Notation

(- \infty, - 1) \cup (- 1, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1, x = 0

The function domain

x < - 1 or - 1 < x < 0 or x > 0

f (x) = 5 x - 7 x + 8

f (x) = \frac{9 x ^{3}}{x - 6}

\frac{x}{x ^{2} + 1}

\frac{- 3 x + 3}{5 x - 5}

f (x) = \frac{- 4}{x - 3}

What is the domain of f(x)= 1/(\frac{x){1/x+1}} ?
The domain of f(x)= 1/(\frac{x){1/x+1}} is x<-1\lor-1<x<0\lor x>0