What is the critical f(x)=3x-6x^3 ?

The critical f(x)=3x-6x^3 is x=-1/(sqrt(6)),x= 1/(sqrt(6))

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critical f(x)=3x-6x^3

critical points

f (x) = 3 x - 6 x^{3}

x = - \frac{1}{6}, x = \frac{1}{6}

Solution steps

3 x - 6 x^{3}

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{1}{6}, x = \frac{1}{6}

Identify critical points not in

f (x)

domain

Domain of

3 x - 6 x^{3} : - \infty < x < \infty

All critical points are in domain

x = - \frac{1}{6}, x = \frac{1}{6}

f (x) = 8 x + 13 x^{\frac{8}{13}}

f (x) = x^{5} - 3 x

f (x) = \frac{x}{4 x}

f (x) = \frac{x + 1}{x - 1}

\frac{1}{( x ^{2} + 1 ) ^{2}}

What is the critical f(x)=3x-6x^3 ?
The critical f(x)=3x-6x^3 is x=-1/(sqrt(6)),x= 1/(sqrt(6))