What is the domain of f(x)= 1/(-5(\frac{1){-x+1})+8} ?

The domain of f(x)= 1/(-5(\frac{1){-x+1})+8} is x 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)= 1/(-5(\frac{1){-x+1})+8}

domain

f (x) = \frac{1}{- 5 ( \frac{1}{- x + 1} ) + 8}

x < \frac{3}{8} or \frac{3}{8} < x < 1 or x > 1

Interval Notation

(- \infty, \frac{3}{8}) \cup (\frac{3}{8}, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{3}{8}, x = 1

The function domain

x < \frac{3}{8} or \frac{3}{8} < x < 1 or x > 1

(2 x^{2} + 1)^{3} (x^{2} - 1)^{2}

f (x) = \frac{( 2 x - 1 )}{2 x + 7}

\frac{x ^{2} + 4 x - 12}{x ^{2} - x - 2}

f (x) = - x - 3 + 2

What is the domain of f(x)= 1/(-5(\frac{1){-x+1})+8} ?
The domain of f(x)= 1/(-5(\frac{1){-x+1})+8} is x< 3/8 \lor 3/8 <x<1\lor x>1