What is the domain of sec^2(x) ?

The domain of sec^2(x) is pin<= x< pi/2+pin\lor pi/2+pin<x<pi+pin

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domain of sec^2(x)

domain

sec^{2} (x)

πn \leq x < \frac{π}{2} + πn or \frac{π}{2} + πn < x < π + πn

Interval Notation

[πn, \frac{π}{2} + πn) \cup (\frac{π}{2} + πn, π + πn)

Solution steps

Take the denominator(s) of

sec^{2} (x)

and compare to zero:

x = \frac{π}{2} + πn

Periodicity of

sec^{2} (x) : π

Combine period:

πn \leq x < π + πn

and undefined points.

The domain is

πn \leq x < \frac{π}{2} + πn or \frac{π}{2} + πn < x < π + πn

x + 4 y = - 8

g (x) = 2 (x - 1)

f (x) = \frac{x - 2}{x ^{2} - 2 x - 8}

f (x) = \frac{x ^{2}}{x ^{2} + 9}

What is the domain of sec^2(x) ?
The domain of sec^2(x) is pin<= x< pi/2+pin\lor pi/2+pin<x<pi+pin